![]() |
X7 BEAM COMPOSITION MEASUREMENTSFor tertiary beams mainly |
The tertiary beam operation of X7 allows to run either hadron beams or electron
beams.
The hadron beams are normally produced by using a Copper target. The
beam contains in general a not quite negligible fraction of electrons or positrons from
pi0 decays. The fraction of electrons (or positrons) may be
reduced by putting 5 or 10 mm lead absorbers into the beam.
Depending on the H3 momentum, electron beams (or positron beams) are
produced either by
In this note we describe how the beam composition of the X7 can be measured
simply from your beam terminal. The first step is to measure the muon content of
the beam. The rest of the beam can be separated in hadron and electron
components, either by studing the effect of different absorber thicknesses on
the beam or by measuring directly using the threshold Cerenkov counters in the
beam.
The procedure is illustrated with measurements done during a summer
student workshop on the 16th of September 1997. At that time the H3 was running
at +250 GeV/c and the X7 at -25 GeV/c.
The beam flux is a linear function of the gap of the momentum slit, COLL-1. In
most cases the measured beam fluxes as a function of COLL-1 slit lie on a
straight line, the extrapolation of which crosses the zero-gap line at a
positive value of flux. This is the muon flux.
Alternatively, one may close COLL-1 and COLL-2 to a 2 mm gap around e.g. +40 mm.
In that case all hadrons and electrons are removed from the beam and one
measures the muon flux directly.
As the muon flux (depending on the ratio of X7 and H3 momenta) may be weak, it is strongly recommended to measure these fluxes with the coincidence of at least 2 counters, either a suitable experimental scaler or (as in the example below) the coincidence of TRIGS 4 and 5.
As explained in the introduction a hadron beam is produced from a 40 cm Copper target, whereas the electron beam is produced either by Bremsstrahlung in a Lead target or by conversion of photons from pi0 decay. Let us denote the total fluxes of these beams, after subtraction of the muon component, by H0 and E0, respectively. H5 and H10 denote the fractions of the hadron beam that survive the presence of 5, respectively 10 mm of Lead absorber. E5 and E10 denote the corresponding quantities in the electron beam. The effect of the absorber is two-fold:
H0 = hh + eh H5 = A hh + B eh H10 = A2 hh + B2 eh |
E0 = he + ee E5 = A he + B ee E10 = A2 he + B2 ee |
where hh and eh denote the hadron and electron components in the hadron beam and he and ee the corresponding components in the electron beam. Now we may assume that B is small (for momenta of 20-50 GeV/c, B is typically 3-4%) and therefore B2 is negligible. Also the electron components in the hadron beam are typically small enough (10-20% or less) to make Beh negligible. In that case some of the equations reduce to:
H5 = A hh (1)
H10 = A2 hh (2)
hence
| A ~ H10 / H5 |
Substitution of this into (2) yields H10 = (H10/H5)2 hh, hence
| hh ~ H52 / H10
eh ~ H0 - H52/H10 |
By neglecting the B2-term in the expression for E10, one finds that E10 ~ A2he and thus
| he ~ E10 H52/H102
ee ~ E0 - E10 H52/H102 |
After some algebra, finally:
| B = ( H102E5 - E10 H10 H5 ) / (E0 H102 - E10 H52 ) |
With this knowledge one may refine the calculations by iteration. In particular one may correct for Beh in the expression for H5 and find a more precise value for A and thus hh and eh.
Example: In the summer student workshop we measured for +250 -> -25 GeV/c the following relative fluxes (the muon component was negligible):
| Absorber | Hadron beam | Electron beam |
| 0 mm | H0 = 1.0 | E0 = 1.0 |
| 5 mm | H5 = 0.68 | E5 = 0.10 |
| 10 mm | H10 = 0.53 | E10 = 0.05 |
Using the above formulae, one finds:
which justifies the approximation B2=0. Then:
he = 8% and ee = 92%
I.e. the hadron beam without absorber contains about 13% of electrons. Adding 5 mm of absorber reduces this by a factor B to 0.5% and 10 mm would reduce it to 0.2 permille. The refinement in the expression for H5 would reduce the value for A hh to A hh = H5 - Beh = 0.68 - 0.005 = 0.675 and thus hh = 0.6752 / 0.53 = 0.86 and eh = 0.14, indeed a small correction only.
Charged particles that travel through a medium with a speed v/c = p/E larger than the velocity of light in that medium (v/c = 1/n where n denotes the refractive index), emit Cerenkov light. In a gaseous medium, the refractive index n is a function of the gas pressure. As electrons (very light) travel faster than (heavier) hadrons of the same momentum, electrons may emit light whereas pions and other hadrons don't, for suitably chosen gas types and pressures. From a given threshold pressure onward, the probability to detect a signal increases slowly from 0 at threshold to almost 1 at high pressures. Taking advantage of these features, threshold Cerenkov counters allow to measure the composition of a beam in terms of different particle types.
A good estimate of electron and pion (hadron) components can be obtained by comparing pressure scans in the hadron and electron beams without absorber. From the pressure scan in the hadron beam one obtains:
The fraction of electrons in the hadron beam eh is equal to
| eh = Se / Ee |
From the scans done during the summer student workshop we found Se = 12.5% and Ee = 89%. This yields eh=14%, in very nice agreement with the absorber method!